As an example, suppose 5 grams of ore gave 3.3 grams of
speise, and 1.1 gram of this gave 0.8 gram of nickel arsenide. Then--
0.8?0.607 = 0.4856 gram of nickel
0.4856?3.3/1.1 = 1.456 gram of nickel
And this being obtained from 5 grams of ore is equivalent to 29.12 per
cent.
When copper is also present, weigh up accurately about 0.5 gram of gold,
and place it on the scorifier with the button of nickel and copper
arsenide, using borax as before. Scorify until the button shows the
bluish-green colour of a fused gold-copper alloy. Then cool, and weigh
the button of copper and gold. The increase in weight of the gold button
gives the copper as metal. The weight of the copper multiplied by 1.395
is the weight of the copper arsenide (Cu_{3}As) present. The difference
will be the nickel arsenide.
The student should enter the weighings in his book as follows:
Ore taken -- grams
Speise got -- "
Speise taken -- grams
Arsenides of cobalt, nickel, and copper -- "
" nickel and copper -- "
Gold added -- "
Gold and copper got -- "
Showing Cobalt -- per cent.
Nickel -- "
Copper -- "
WET METHODS.
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